With perpendicular incidence, approximately what percent of the incident beam is transmitted?

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Multiple Choice

With perpendicular incidence, approximately what percent of the incident beam is transmitted?

Explanation:
At normal incidence, the boundary between two media lets energy transmit most efficiently when their acoustic impedances are very similar. The amount reflected is governed by the normal-incidence reflection coefficient R = ((Z2 − Z1)/(Z2 + Z1))^2. For soft tissues, Z1 and Z2 are close (about 1.6 MRayls), so the mismatch is small and R is around 1% or less. Transmission is then roughly 1 − R, which is about 99%. So almost all the energy passes into the next medium, with only a tiny fraction reflected. That's why about 99% transmitted is the best answer. The remaining energy is absorbed or scattered within the tissue, and any slight mismatch prevents a full 100% transmission.

At normal incidence, the boundary between two media lets energy transmit most efficiently when their acoustic impedances are very similar. The amount reflected is governed by the normal-incidence reflection coefficient R = ((Z2 − Z1)/(Z2 + Z1))^2. For soft tissues, Z1 and Z2 are close (about 1.6 MRayls), so the mismatch is small and R is around 1% or less. Transmission is then roughly 1 − R, which is about 99%. So almost all the energy passes into the next medium, with only a tiny fraction reflected. That's why about 99% transmitted is the best answer. The remaining energy is absorbed or scattered within the tissue, and any slight mismatch prevents a full 100% transmission.

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